if the HCF of 2 numbers is 5 if their LCM is
180 and one of the no is 45, find the other no
Answers
Answered by
0
As we know
LCM × HCF = Product of two numbers
LCM = 180
HCF = 5
one number = 45
let other number be y
therefore,
180 × 5 = 45 × y
900 = 45 × y
900/45 = y
y = 20
other number is 20
Answered by
0
Answer:
20
Step-by-step explanation:
HCF * LCM = Product of two numbers
5 * 180 = 45 * x
900 = 45x
x = 900/45
x = 20
The other number is 20
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