Question

if the hcf of 210 and 55 is expressible in the form 201*5+55y then find y

Answer 1

The HCF of 210 and 55 is 5
so,
            5 = 210*5 + 55y
     -1045 = 55y
             y = -1045 / 55
             y = -19    

Answer 2

210=5*2*3*7

55=5*11

HCF=5

210*5*55y=5

1050+55y=5

55y=5-1050

    =-1045

y=-1045/55=-19