Question

If the HCF of 210 and 55 is expressible in the form of 210 x 5 + 55P, then value of P = ?

Answer 1

210= 55 * 3 + 45  

55 = 45 * 1 + 10  

45 = 4 * 10 + 5  

10 = 5 * 2 + 0  

H.C.F = 5  

Therefore, 5 = 210 * 5 + 55P

55P = 5 - 210 * 5 = 5 - 1050  

55P = -1045  

P= -1045/55  

P= -19

Answer 2

Answer:

P=-19

Step-by-step explanation:

Using division lemma on 210 and 55

210=55*3+45---------------(1)

Using division lemma on 55 and 45

55=45+10---------------------------(2)

Using division lemma on 45 and 10

45=10*4+5------------------------(3)

Using division lemma on 10 and 5

10=2*5+0

HCF of 210 and 55=5

Now

HCF  5=210 x 5 + 55P

55P=5-210*5=5-1050=-1045

55P=-1045

P=-1045/55

P=-19