if the HCF of 210 and 55 is in the form 210 ×5+55y . find y
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210=55X3+45
55=45X1+10
45=10X4+5
10=5X2+0
HCF=5
HCF=X=5
210X5+55
1050+55Y=0
55Y=-1050
Y=-1050/55=-19
55=45X1+10
45=10X4+5
10=5X2+0
HCF=5
HCF=X=5
210X5+55
1050+55Y=0
55Y=-1050
Y=-1050/55=-19
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