Question

If the HCF of 210 and 55 is of the form 210(5) + 55y ,then find y

Answer 1

Answer:

Heya !!

we know the formula a = bq + r

210 = 55 × 3 +45 say it is eq . 1)

55 = 45 ×1 + 10 2)

45 = 4×10 +5 3)

now we consider the divisor 10 and the remainder 5 and apply DL to get

10 = 5×2 +0

we observe here that r =0 and our present divisor which is 5 will be it HcF

A/Q

5 = 210 ×5 + 55y

55y = 5 - 210×5

= 5 - 1050

y = - 1045 /55

y = -19

Hope this helps u plzz mark it as brainliest

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

HCF (210,55) = 5

Then,

210(5) + 55y = 5

=> 5(210 + 11y) = 5

=> 210 + 11y = 1

=> y = -209/11

=> y = -19