if the hcf of 26 and 65 is expressible as 26m-65, then find the value of m
Answers
Answered by
2
Answer:3
Step-by-step explanation:
Hii friend,
Prime factorisation of 26 = 2 × 13
Prime factorisation of 65 = 5 × 13
Therefore,
HCF of 26 and 65 = 13
26m - 65 = 13
26m = 13+65
26m = 78
m = 78/26
m = 3.
Hence,
m = 3
Answered by
1
Answer:
hcf of 26 and 65=13
13=26m-65
26m=78
m=78/26
m=3
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