Math, asked by herofortyseven43537, 11 hours ago

if the hcf of 26 and 65 is expressible as 26m-65, then find the value of m​

Answers

Answered by grrewalsnishka
2

Answer:3

Step-by-step explanation:

Hii friend,

Prime factorisation of 26 = 2 × 13

Prime factorisation of 65 = 5 × 13

Therefore,

HCF of 26 and 65 = 13

26m - 65 = 13

26m = 13+65

26m = 78

m = 78/26

m = 3.

Hence,

m = 3

Answered by shivashankarchelumal
1

Answer:

hcf of 26 and 65=13

13=26m-65

26m=78

m=78/26

m=3

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