If the HCF of 26xand65 is expressed in the form 26x-65 then find the value of c
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Hii friend,
Prime factorisation of 26 = 2 × 13
Prime factorisation of 65 = 5 × 13
HCF of 26 and 65 = 13
therefore,
26X -65 = 13
26X = 13+65
26X = 78
X = 78/26
X = 3
HOPE IT WILL HELP YOU..... :-)
Prime factorisation of 26 = 2 × 13
Prime factorisation of 65 = 5 × 13
HCF of 26 and 65 = 13
therefore,
26X -65 = 13
26X = 13+65
26X = 78
X = 78/26
X = 3
HOPE IT WILL HELP YOU..... :-)
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