Math, asked by sandy29, 1 year ago

If the HCf of 306 and 657 is expressible in the form 306*15-657*y .find y

Answers

Answered by kavya14
0
HCF(657,306) = 9

Therefore 9 = 306*15-657*y
9= 4590-657*y
657*y = 4581
y= 509÷ 73

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