Question

if the hcf of 408 and 1032 is expressible in the form 1032m-408*5 find m and n

Answer 1

where is my in the question..
pls check the question and ask again..

Answer 2

First find out the hcf

1032=408×2 + 216

408=216×1 + 192

216=192×1 + 24

192=24×8 + 0

so, now since the remainder has come zero

so the hcf will be 24

now if we put hcf=1032-408×5

1032m-408×5=24

1032m-2040=24

1032m=24+2040⇒2064

m=2064÷1032⇒2

2 is the value of m.