if the hcf of 420 and 110 is expressible in the from of 420×5+110x findx
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36
Euclid's division lemma:-
a=bq+r
0 ≤ r ≤ b
420 = 110 × 3 + 90
110 = 90 × 1 + 20
90 = 20 × 4 + 10
20 = 10 × 2 + 0
HCF of 420 and 110 is 20.
20 is expressed in the form 420×5+110x
20 = 420(5) + 110x
20 = 2100 + 110x
110x = 20-2100
110x = -2080
x = -2080/110
x = -18.90 (approx.)
Hope it helps
a=bq+r
0 ≤ r ≤ b
420 = 110 × 3 + 90
110 = 90 × 1 + 20
90 = 20 × 4 + 10
20 = 10 × 2 + 0
HCF of 420 and 110 is 20.
20 is expressed in the form 420×5+110x
20 = 420(5) + 110x
20 = 2100 + 110x
110x = 20-2100
110x = -2080
x = -2080/110
x = -18.90 (approx.)
Hope it helps
Answered by
10
a=bq+r
0 ≤ r ≤ b
420 = 110 × 3 + 90
110 = 90 × 1 + 20
90 = 20 × 4 + 10
20 = 10 × 2 + 0
HCF of 420 and 110 is 20.
20 is expressed in the form 420×5+110x
20 = 420(5) + 110x
20 = 2100 + 110x
110x = 20-2100
110x = -2080
x = -2080/110
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