Question

If the HCF of 420 and 130 is expressible in the form 420p + 130g, then value of p + qis:
(A) 17
(B) 6
(C) 5
(D) 9​

Answer 1

Answer:

(D)9

Step-by-step explanation:

H.C.F. of 420 and 130 =2¹×5¹=10

Let p= -4 and q=13 then

420p+130q=(420×-4)+130×13

= -1680+1690

=10 (i.e.,H.C.F. of 420 and 130)

p+q= -4+13

p+q=9