Question

If the HCF of 45 and 55 is 5 LCM of 45 and 55 is 99*A then the value of A is​

Answer 1

Answer:

Answer is 495

Step-by-step explanation:

explanation is 3x3x5x11 = 495

Answer 2

Answer:

The value of $A=5.$

Step-by-step explanation:

Given:

If the HCF of 45 and 55 is 5 then the LCM of 45 and 55 is $99 * A$.

To find the value of A.

Step 1

To find the LCM of 45 and 55

The LCM of $a, b$ is the smallest positive number that is divisible by both $a$and $b$

Prime factorization of 45 :

$3 \cdot 3 \cdot 5$

Prime factorization of 55:

$\quad 5 \cdot 11$

Multiply each factor the greatest number of times it occurs in either 45 or 55

$=3 \cdot 3 \cdot 5 \cdot 11$

Multiply the numbers:

$3 \cdot 3 \cdot 5 \cdot 11=495$

Step 2

So, The LCM = 495

If, $99 * A = 4$

$a = \frac{495}{99}$

$a = 5$

Therefore, the value of $A=5.$

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