. If the HCF of 55 and 99 is expressible in the form 55m � 99, then the value of m is: (a) 4 (b) 2 (c) 1 (d) 3
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Answered by
59
Prime factorization of 55 = 5 * 11
Prime factorization of 99 = 3 * 3 * 11
HCF(55,99) = 11.
Now,
55m - 99 = 11
55m = 99 + 11
55m = 110
m = 2.
Therefore the value of m = 2.
Hope this helps!
Prime factorization of 99 = 3 * 3 * 11
HCF(55,99) = 11.
Now,
55m - 99 = 11
55m = 99 + 11
55m = 110
m = 2.
Therefore the value of m = 2.
Hope this helps!
Answered by
27
Hi,
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Please see the attached file !
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