Question

if the hcf of 65 and 117 is expessible in the form 65m-117, then hcf (a,b)is equal to (a)x³y³ (b) xy (c)x²y (d)xy²​

Answer 1

Answer:

Showing results for if the hcf of 65 and 117 is expressible in the form 65m-117, then hcf (a,b)is equal to (a)x³y³ (b) xy (c)x²y (d)xy²

Step-by-step explanation:

Correct option is

B

2

65= 5×13

117= 3×3×13

Therefore, HCF of 65 and 117 is 13.

So, 65m−117=13

or, 65m=130

Therefore, m=2