if the HCF of 65 and 117 is expressible in the following 65m-117, then the value of m is ....
Answers
Answered by
46
ur answer is 2
Step-by-step explanation:
By Euclid’s division algorithm
b=aq+r
117=65×1+52
65=52×1+13
52=13×4+0
H.C.F(65,117)=13
Since H.C.F =65m-117
so, 65m-117=13
=65m=13+117=130
=m=130/65=2
Answered by
3
QUESTION -
if the HCF of 65 and 117 is expressible in the following 65m-117, then the value of m is ....
if the HCF of 65 and 117 is expressible in the following 65m-117, then the value of m is ....
ANSWER -
let us find the HCF of 65 and 117,
117 = 1×65 + 52
65 = 1× 52 + 13
52 = 4 ×13 +0
therefore HCF of 65 and 117 is 13.
65m-117 = 13
65m = 117+13 = 130
m =130/65 =2
Now,
65 = 5 × 13
117 = 13 × 3 × 3
LCM of 65 and 117 = 5 × 13 × 3 × 3 = 585
@HarshPratapSingh
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