If the HCF of 65 and 117 is expressible in the
form 65 m - 117, then the value of m is:
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Answered by
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Answer:
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HCF (65,117) =65m-117 equation 1
65)11(1. 65/52)65(1/52 /13)52(4/52/0. therefore HCF (65,117)=13 equation 2 from 1 and 2 13=65 m -17 =13+117=65m=130=65m=m=2
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