if the hcf of 65 and 117 is expressible in the form 65,x-117 ,then the value of x is
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Hi there!
Given,
HCF of 65 n' 117 is expressible in form 65x - 117
117 = 1 × 65 + 52
65 = 1 × 52 + 13
52 = 4 ×13 + 0
∴ HCF of 65 and 117 is 13.
ATQ,
65x - 117 = 13
65x = 117 + 13 = 130
∴ x = 130/65
Thus,
x = 2
Hope it helps! :D
Cheers,
Ishaan Singh
Given,
HCF of 65 n' 117 is expressible in form 65x - 117
117 = 1 × 65 + 52
65 = 1 × 52 + 13
52 = 4 ×13 + 0
∴ HCF of 65 and 117 is 13.
ATQ,
65x - 117 = 13
65x = 117 + 13 = 130
∴ x = 130/65
Thus,
x = 2
Hope it helps! :D
Cheers,
Ishaan Singh
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