Question

If the HCF of 65 and 117 is expressible in the form 65m-117,then the value of the m is?​

Answer 1

Let us find the HCF of 65 and 117,

117 = 1 × 65 + 52

65 = 1 × 52 + 13

52 = 4 ×13 + 0

therefore HCF of 65 and 117 is 13.

65m -117 = 13

65m = 117+13 = 130

m =130 / 65 =2

Now, 65 = 5 × 13

117 = 13 × 3 × 3

LCM of 65 and 117 = 5 × 13 × 3 × 3 = 585

Answer 2

Answer:

m = 2

Step-by-step explanation:

HCF of 65 and 117 = 13

65m - 117 = 13

65m = 13 + 117

65m = 130

m = 130/65

m = 2