If the HCF of 65 and 117 is expressible in the form of 65m – 117 then the value of m is
1) 4 2) 2 3) 1 4) 3
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65= 5×13
117= 3×3×13
Therefore, HCF of 65 and 117 is 13.
So, 65m−117=13
or, 65m=130
Therefore, m=2
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