If the hcf of 65 and 117 is expressible in the form of 65m-117 then the vale of m is?
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the hcf of 65 and 117 is 13.
now , the hcf is in form of 65m-117 which is equal to 13
13=65m-117
65m=130
m=2
now , the hcf is in form of 65m-117 which is equal to 13
13=65m-117
65m=130
m=2
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