Math, asked by attrikapil316, 19 days ago

if the hcf of 65 and 117 is the expressible for 65m-117 then the value of m is​

Answers

Answered by aarnakhatri8
1

Answer:

4help help help him

Step-by-step explanation:

2+2 -4 ok

help help

Answered by shravanipatil112006
1

Answer:

2

Step-by-step explanation:

We have been given in the question that if the HCF of 65 and 117 is expressible in the form 65m – 117, then we have to find the value of m.

Before we proceed with the question, let us first understand what an HCF or the highest common factor is. HCF is the factor with the highest value that is common to the numbers whose HCF is taken.

For example, the HCF of the numbers 40 and 15 is 5.

So, we will find the HCF of the numbers 65 and 117. So, we can write their factors first, so we get,

65=5×13117=3×3×13

So, from the factors of 65 and 117, we can see that 13 is the highest common factor. Hence, we get the HCF as 13.

Now, we also have the expression for the HCF of 65 and 117 as 65m – 117. So, we will equate this expression to the value of HCF. So, we will get,

65m – 117 = 13

On adding 117 to both the sides of the above equation, we get,

65m = 13 + 117

65m = 130

On dividing both the sides by 65, we get,

m=13065

m = 2

Therefore, we get the value of m as 2.

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