Question

if the hcf of 65 and 117is expressible in the form 6m-117 then the value of m is​

Answer 1

Answer:

Let us find the HCF of 65 and 117,

117 = 1 × 65 + 52

65 = 1 × 52 + 13

52 = 4 ×13 + 0

therefore HCF of 65 and 117 is 13.

65m -117 = 13

65m = 117+13 = 130

m =130 / 65 =2

Now, 65 = 5 × 13

117 = 13 × 3 × 3

LCM of 65 and 117 = 5 × 13 × 3 × 3 = 585

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