Math, asked by pb179195, 1 month ago

If the HCF of 657 and 963 is expressed as 657m+ 963n (where m and n are integers) then what is the value of 'm'?

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Answered by Devid333

The HCF is the product of all common factors. We now equate 657x−(963×15) to 9. We know that 14454 is obtained by 22 multiplied with 657, hence, when 14454 is divided by 657, we get 22. Hence, the value of x is 22.

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If the HCF of 657 and 963 is expressed as 657m+ 963n (where m and n are integers) then what is the value of 'm'?​

Answers

If the HCF of 657 and 963 is expressed as 657m+ 963n (where m and n are integers) then what is the value of 'm'?