If the HCF of 657 and 963 is expressible in form of 657x × 963 × (-15).find the value of x.
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Using Euclid’s Division
a= bq+r
963=657×1+306
657=306×2+45
306=45×6+36
45=36×1+9
36=9×4+0
∴HCF is 9
9=657x - (963*15)
657x= 14454
X=22
a= bq+r
963=657×1+306
657=306×2+45
306=45×6+36
45=36×1+9
36=9×4+0
∴HCF is 9
9=657x - (963*15)
657x= 14454
X=22
mansimj2003:
Hey mate in this line it should be (-) sign
Before 15
hmm
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Aapko kya krna ji hm kahi se bhi ho
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byyyyy
kha pe
9=657x - (963*15) in this line before 15
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