If the HCF of 657 and 963 is expressible in the form of 657m+963n then find the value of m
Answers
Answered by
0
Answer:
m=22
Step-by-step explanation:
In place of n there should be -15
By Euclid's division algorithm
963=657×1+306
657=306×2+45
306=45×6+36
45=36×1+9
36=9×4+0
Since the reminder becomes here so HCF of 657 and 963 is 9 Now
657m+963×(−15)=HCF of these number
657m+963x(−15)=9
657m=14454
m=22
Similar questions