Question

If the hcf of 81 and 237 can be written as 237 m + 81 and then find the value of m and n

Answer 1

Given:

The hcf of 81 and 237 can be written as 237 m + 81  

To find:

Find the value of m and n

Solution:

Using Euclid's Division Algorithm, we have,

237 = 81(2)+(75)  → 81 = 75(1) + (6)  → 75 = 6(12)+(3)  → 6 = 3(2)+(0)

∴ The hcf of 81 and 237 = 3

Expressing the hcf in the form of 237m + 81n = HCF

3 = 75 - 6(12)

3 = 75 - (81 - 75) (12)

3 = 75 - 81(12) + 75(12)

3 = 75(13) - 81(12)

3 = (237 - 81 × 2) (13) - 81(12)

3 = 237(13) - 81(38)

∴ 3 = 237(13) + 81(-38)

Therefore, the values of m and n are 13 and - 38 respectively

Answer 2

Answer:

guuuuuu

Step-by-step explanation:

nejdjdjdjdhdhd