If the HCF of (p²-p-6) and (p²+3p-18) is (p-a). Find the value of a.
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Answers
Answered by
15
Answer:
3
Step-by-step explanation:
p^2 - p -6
= p^2 -3p + 2p - 6
= (p-3)(p+2)
p^2 + 3p - 18
= p^2 + 6p - 3p -18
= (p+6)(p-3)
p-3 is common factor
so p-a = p-3
a = 3
rustyattacker03629:
nice, but you can take the factor p-a first i.e. p=a
Mark as brainliest if it helped
it helps a lot thnx
so you found other answer as brainliest
sorry, for next time i will you mark as BRAINIEST
anyways thanks
Answered by
19
Answer:
a = 3
Step-by-step explanation:
(i)
p² - p - 6
= p² + 2p - 3p - 6
= p(p + 2) - 3(p + 2)
= (p - 3)(p + 2)
(ii)
p² + 3p - 18
= p² - 3p + 6p - 18
= p(p - 3) + 6(p - 3)
= (p + 6)(p - 3)
Hence, HCF (p - 3)(p + 2) and (p + 6)(p - 3) is (p - 3).
Now,
(p - 3) = p - a
On comparing both sides, we get
a = 3.
Hope it helps!
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