If the HCF of two mumbers 17and LCM is 1309, which of the given optuons could be one of the numbers
a 167
b 119
c 153
d 170
Answers
Step-by-step explanation:
Given that HCF of two numbers = 17
LCM of two numbers=1309
We know that HCF × LCM= product of two numbers
Now, 17 ×1309= product of two numbers
17 ×17×7×11=product of two numbers
(17×7)×(11×17)=product of two numbers
let A and B be two number
Now , A×B=(17×7)×(17×11)
we can say that A can be(17×7)&B can be (17×11) or A can be (17×11)&B can be(17×7).
clearly,A=119or187
B=187or119
hence, correct option is (b)119
thanks
Given : HCF of two numbers is 17 and LCM is 1309,
To Find : what could be one of the two numbers
Solution:
HCF of two numbers is 17
Hence two numbers are
17a and 17b where a , b are co prime numbers
HCF * LCM = Product of numbers
=> 17 * 1309 = 17a * 17b
=> 77 = a * b
77 = 1 * 77 = 7 * 11
a = 1 , 7 , 11 , 77
17a = 17 , 119 , 187 , 1309
Hence one of the number can be
17 , 119 , 187 , 1309
Hence from the given options 119 is the correct answer.
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