Math, asked by bushiman, 1 year ago

If the HCF of two no is 9 and those LCM is 459 . If one of the no is 27, find the other

Answers

Answered by naveekutty2
9
Given,

 H.C.F = 9

 L.C.M = 459.

 One of the numbers = 27.

 Other number = ?

Let another number is a.

We know that,

 L.C.M x H.C.F = Product of numbers

  459 x 9 = 27 x a

  4,131 = 27 a

  a = 4,131 / 27

  a = 153.

So, another number is 153.

naveekutty2: Thanks
bushiman: never mind
Answered by Brainly100
1
Hii Mate here is your answer,

We can easily solve this question by a Formula,

i.e. LCM × HCF = Product of the two numbers

It means that When we find LCM and HCF of two numbers then the product of LCM and HCF is equals to product of two numbers.

A/Q : GIVEN
HCF= 9
LCM= 459
First NO.= 27
Second no.= ?

So let us proceed.........

LCM × HCF = No.1 × No.2

459×9 = 27 × No.2

= No.2 = (459×9)/17

No.2 = 153

Hence, the another number is 153

● This rule is applicable for Finding HCF and LCM of only two numbers not more than that.

♤♢♧ Hope this helps you a lot......☺☺
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