If the hcf of two number is 12 and their lcm is 180. If one of the number is 36, find the other.
Answers
Answered by
142
Product of 1st n 2nd no. = LCM ×HCF
36 ×2nd no. = 180 × 12
2nd no. = 180 × 12 /36
= 60...... Ans
I hope its helpful..
36 ×2nd no. = 180 × 12
2nd no. = 180 × 12 /36
= 60...... Ans
I hope its helpful..
Answered by
66
Hcf=12
Lcm=180
One of the two numbers=36
Then,
we had know that Lcm=(Product of the numbers)/Hcf
Let,
the other number be x
Then,
180=(36×x)/12
=>180=36x/12
=>x=(180×12)/36
=>x=2160/36
=>x=60
Lcm=180
One of the two numbers=36
Then,
we had know that Lcm=(Product of the numbers)/Hcf
Let,
the other number be x
Then,
180=(36×x)/12
=>180=36x/12
=>x=(180×12)/36
=>x=2160/36
=>x=60
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