Question

if the HCF of (x²+x-12 )and
(2x²-kx-9) is (x-k) find the
value of 'k' ?
PLEASE GUYS IT'S URGENT... ​

Answer 1

Answer:

3

Step-by-step explanation:

by factorise we find this value

Answer 2

Answer:

3

Step-by-step explanation:

zero of x-k = k

given that x- k is the factor of 2x² - kx -9 then

p(k) = 0

2k²-k-9 = 0

2k²-k*k= 9

2k²- k² = 9

k² = 9

k = √ 9

k = 3