Math, asked by tomba7774, 10 months ago

if the hck of 210 and 55 is expressible in the form 210×5+55y then find y

Answers

Answered by bhadoriavatsal2gmail

Step-by-step explanation:

HCF of 210 and 55 = 5

ATC

210×5+55y =5

1050+55y =5

55y =5-1050

55y = -1045

y = -1045/55

y = -19

Answered by Anonymous

Answer:

Step-by-step explanation:

Apply Division lemme on 210 and 55

210=55*3+45

Apply Division lemme on 55 and 45

55=45*1+10

Apply Division lemme on 45 and 10

45=10*4+5

Apply Division lemme on 10 and 5

10=5*2+0

Hence HCF=5

Given

HCF=210*5+55y

5=1050+55y

55y=1050-5=-1045

y=-1045/55=-209/11

Anonymous: oh y=-209/11=-5

bhadoriavatsal2gmail: I think you have done wrong division

bhadoriavatsal2gmail: you can multiply 11×19 it will be 209

Anonymous: Yah -209/11=-19 but this much students can understand these are typing mistakes.For such mistakes normally good examiner do not deduct marks

Anonymous: We should not try to catch other's mistake but copy good qualities.These are qualities of good persons

Anonymous: Jaise apne sunahoga"jaisee hamari soch hoti hai baise hum life main ban jate hain"

bhadoriavatsal2gmail: you have only started this I haven't first make yourself correct then say to others

Anonymous: ok jaisee tumharee soch,you are correct ,bye...good bye

bhadoriavatsal2gmail: ok I also don't talk to you more and learn to accept your mistakes

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