if the hck of 210 and 55 is expressible in the form 210×5+55y then find y
Answers
Answered by
2
Step-by-step explanation:
HCF of 210 and 55 = 5
ATC
210×5+55y =5
1050+55y =5
55y =5-1050
55y = -1045
y = -1045/55
y = -19
Answered by
3
Answer:
Step-by-step explanation:
Apply Division lemme on 210 and 55
210=55*3+45
Apply Division lemme on 55 and 45
55=45*1+10
Apply Division lemme on 45 and 10
45=10*4+5
Apply Division lemme on 10 and 5
10=5*2+0
Hence HCF=5
Given
HCF=210*5+55y
5=1050+55y
55y=1050-5=-1045
y=-1045/55=-209/11
Anonymous:
oh y=-209/11=-5
I think you have done wrong division
you can multiply 11×19 it will be 209
Yah -209/11=-19 but this much students can understand these are typing mistakes.For such mistakes normally good examiner do not deduct marks
We should not try to catch other's mistake but copy good qualities.These are qualities of good persons
Jaise apne sunahoga"jaisee hamari soch hoti hai baise hum life main ban jate hain"
you have only started this I haven't first make yourself correct then say to others
ok jaisee tumharee soch,you are correct ,bye...good bye
ok I also don't talk to you more and learn to accept your mistakes
Similar questions