Question

If the heat of ammonia gas at 298 Kand 348 K was found to be -11.04 Kcal and -253.79 Kcal respectively. Calculate change in heat capacity at constant pressure for ammonia. ​

Answer 1

Answer:

N

2

+3H

2

→2NH

3

Δn=2−(1+3)=−2

ΔH=ΔU+ΔnRT

ΔU=ΔH−ΔnRT

ΔU=−42.0 kJ/mol−[(−2)×8.314×10

−3

kJ/mol/K×298 K]

ΔU=−37.0 kJ/mol