If the heat of atomization of PH3(g) is x1 kJmol–1 and bond energy of P-P bond is x2 kJmol–1 then heat of atomization in kJmol–1 of P2H4(g) will be
A x1+x2. B. X1-X2. C X2 + X1/X3. D. X2+4X1/3
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Answer:
Hello mate itz Essar 03
Explanation:
The balanced chemical equation for the atomization of phosphine is PH
3
⟶P+3H;ΔH=228
e
p−−H
=
3
228
The balanced chemical equation for the atomization of P
2
H
4
(g) is H
2
P−−PH
2
⟶2P+4H;ΔH=355
e
p−−p
+4×e
p−−H
=355
e
p−−p
+4×
3
228
=355
e
p−−p
=51
The energy of the P−−P bond is 51 kcal.
hope it will be helpful ✌️✌️✌️✌️❤️❤️
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