Question

If the heat of atomization of PH3(g) is x1 kJmol–1 and bond energy of P-P bond is x2 kJmol–1 then heat of atomization in kJmol–1 of P2H4(g) will be
A x1+x2. B. X1-X2. C X2 + X1/X3. D. X2+4X1/3

Answer 1

Answer:

Hello mate itz Essar 03

Explanation:

The balanced chemical equation for the atomization of phosphine is PH

3

⟶P+3H;ΔH=228

e

p−−H

=

3

228

The balanced chemical equation for the atomization of P

2

H

4

(g) is H

2

P−−PH

2

⟶2P+4H;ΔH=355

e

p−−p

+4×e

p−−H

=355

e

p−−p

+4×

3

228

=355

e

p−−p

=51

The energy of the P−−P bond is 51 kcal.

hope it will be helpful ✌️✌️✌️✌️❤️❤️