Question

. If the height AB of a pole is 2√3 meters and the length of it shadow AC is 2 meters, then find the length of BC.

Answer 1

Answer:

Let AB be the pole and AC be its shadow.

Let angle of elevation, ∠ACB=θ

Then, AB=2√3m and AC=2 m.

tanθ=AB/AC =2√3/2

⇒θ=60 ∘