If the height and and sum of parallel sides of a trapezium are increased three times, then find the increase percent of area.
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Question :-
If the height and sum of parallel sides of a trapezium are increased three times then, find the increase percent of area.
Answer :-
Area of trapezium = 1/2 × Sum of parallel sides × Distance between them
a and b are the sides of it.
all are increasing by three times then area 3a plus 3b by 2 multiplying by 3height
then new area is 9 times of first are
then increasment is 8 times of first area then increase percentage is 800%
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Hey mate here is your answer
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