Question

If the height and radius of volume V is doubled then what will be the volume of the cone

Answer 1

Answer:

Let actual radius be r.

Let actual height be h.

Actual volume of cone = V

$= \frac{1}{3} \pi \: r \: h$

After being doubled,

height = 2h

radius = 2r

Volume,V':

$= \frac{1}{3} \times \pi \times 2r \times 2h$

$4 \times \frac{1}{3} \pi \: r \: h$

V'/V = 4

Therefore, after the height and radius being doubled, the volume of cone increase by 4 times.

Hope this answer helps you ^_^ !