if the height and sum of the parallel sides of a trapezium are increased three times, then find the increase per cent of area .
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Where, a and b are parallel sides and h is perpendicular height.
Where, a and b are parallel sides and h is perpendicular height.So, (a+b) is sum of length of bases of a trapezium.
Where, a and b are parallel sides and h is perpendicular height.So, (a+b) is sum of length of bases of a trapezium.Now,
⇒ a+b=300cm
⇒ a+b=300cmWas this answer helpful?
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