Question

If the height of a chimney is (60m) and the height of 100 brick is 3m,then find the number of brick used​

Answer 1

Step-by-step explanation:

Given -

height of a chimney is (60m) and the height of 100 brick is 3m

To find -

find the number of brick used

Solution ✅ -

Height of chimney → 60m = 6000 cm

Height of 100 brick ′→ 3 m (300cm)

Then height of 1 brick – 3 cm

total bricks —». 6000/3 ≈ 2000

Äñswêr ♥♠ → 2000

Answer 2

Answer:

100 number of bricks were used.

Step-by-step explanation:

Given height of a chimney is 60 m and height of 100 bricks is 3 m.

If height of 100 bricks is 3 m

then height of 1 bricks is

$\frac{3}{100} = \frac{3}{100} \: m$

So,for $\frac{3}{100} \: m$ height we need 1 brick

By Unitary method,

for 1 m height we need $\frac{1}{ \frac{3}{100} }$ brick.

And for 60 m height,we need

$\frac{1}{ \frac{3}{100} } \times 60 \\ = \frac{100}{3} \times 60 \\ = 100 \times 20 \\ = 2000 \: bricks$

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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