Question

if the height of a solid right circular cylinder is 6 cm and diameter 14 cm final the area of the whole surface
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Answer 1

Ans : 571.48

Step-by-step explanation:

A = 2πr² + 2πrh

= 2 (3.14) 7² + 2 (3.14) × 7 × 6

= 6.28 × 49 + 6.28 × 42

= 307.72 + 263.76

= 571.48

Answer 2

Answer :

• 572 cm²

Given :

• Height of the right circular cylinder = 6 cm
• Diameter of the right circular cylinder = 14 cm

To find :

• area of the whole surface

Solution :

⇒ Let's find the Radius.

Radius = Diameter/2

= 14/2

= 7 cm

⇒ Let's find the area of the whole surface.

Here,

• π = 22/7
• Radius = 7 cm
• Height = 6 cm

→ Area of the whole surface = 2πr(h+r)

→ 2 × 22/7 × 7 × (6 + 7)

→ 2 × 22/7 × 7 × 13

→ 2 × 22/7 × 91

→ 2 × 91 × 22/7

→ 182 × 22/7

→ 4004/7

→ 572

∴ 572 cm²

• Therefore, the area of the whole surface of a solid right circular is 572 cm².