Question

If the height of a tower is 20 m, then find the length of its shadow when Sun’s altitude is 30°

explain with steps​

Answer 1

Answer:

From the figure,

Height of the tower = AB = 20 m

Length of the shadow = BC = 20√3

the altitude of the Sun = <ACB

tan <ACB = AB/CB

= 20/20-√3

=1/√3

tan <ACB= tan 30"

<ACB = 30⁰

I hope this helps you.

Step-by-step explanation:

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Answer 2

Hey,

GIVEN:- height of tower i.e., AB = 20m.

In fig. AB is the height of tower ,

let BC is the length of the shadow of tower when altitude is 30° i.e ., the angle of elevation of the top of the tower from the tip of the shadow is 30°

using trigonometry ratios,

we know:- tan∅ = perpendicular/base

IN ∆ABC,

tan30° = AB/BC

1/√3 = 20/BC

BC = 20√3m

hence,the length of the shadow of tower is 20√3m