if the height of a triangle is a square minus b square and its base is 12 ab its area is
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Let the base of the triangle = B m, and so the height = (B-10) m.
Area of the triangle = B(B-10)/2 = 12, or
B(B-10) = 24, or
B^2–10B-24 = 0, or
(B-12)(B+2) = 0, or
B = 12 m and the height = (12–10) = 2 m.
The base of the triangle is 12 m. Answer.
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Answer:
Area of triangle is 6a²b² cm
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