Math, asked by midhumurali728, 9 months ago

if the height of clinometer is 3 meter, distance between building and clinometer is 27m and angle of elevation is 45 degree what is the height of the building​

Answers

Answered by akubaria12
9

Step-by-step explanation:

Tan45 = height/base

Let height of building be x

Clinometer is at 3m height therefore

Apparent Height of building will be x-3

Base =27 meters

Tan45=1

So

1= x-3/27

27=x-3

X= 27+3

Therefore height of building = 30 meters

Answered by akshitasinghpatel1
2

Answer:

Given:

angle = 45°

(h) of clinometer = 3m

Base = 27m

Let height of building = xm

sub (h) of clinometer with the h of building= x-3

use tan 45°

:- tan 45= x-3/27

:- 1 = x-3/27

:- 27 +3 = x

:- 30. =x

Similar questions