Question

If the height of solid cylinder is h and cross sectional area is a with the density 1.40 *10000 kg metre cube they are immersed completely in a mixture of liquid such that floats with its Axis vertical at the liquid liquid interface with land liquid to liquid in less intense liquid the less intense liquid is open to atmospheric pressure p the density of 1.0 *10000 kg metre per cube then density of liquid will be?

Answer 1

The density of denser liquid will be dl2 = 2.6 x 10^3 kg/m^3.

Explanation:

Cross sectional area of cylinder = A

Density of cylinder = 1.40 x 1000 kg / m^3

V(im) / V to = do / dl

do = dl [ V(im)/V(to) + dl2 [V (im2) / Vto ]

1.4 = 1 (3/4) +x (1/4)

14/10 -3/4 = x / 4

4 ( 28 - 25)/ 20 = x

x = dl2 = 18/5 = 2.6 x 10^3 kg/m^3

dl2 = 2.6 x 10^3 kg/m^3

Hence the density of denser liquid will be dl2 = 2.6 x 10^3 kg/m^3.

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