Question

if the height of the cone is three times the radius of the base and it's volume of512pie cubic cm then find the radius of the base of the cone​

Answer 1

h=3r

v=512 π

512π = I/3πr 2h

512π = I/3πr 2x3r

512π = πr^3

r^3 = 512π/π=512

r =3 v512 = 8

RADIUS=8cm

Answer 2

Answer:

The correct answer of this question is 8cm

Step-by-step explanation:

Given - The height of the cone which is three times the radius of the base and it's volume of512pie cubic cm

Find - Find the radius of the base of the cone​.

The height of the cone which is three times is h =3r

volume is = 512$\pi$

512$\pi$ = $\frac{1}{3\pi r}$ 2h

512$\pi$ = $\frac{1}{3\pi r}$ 2× 3r

512$\pi$ =  $\pi r^{3}$

$r^{3} =\frac{512\pi }{\pi } = 512$

r = 3 ∨512 = 8

Radius is 8cm