Question

If the height of the cone is tripled and the radius is doubled, what is its volume ?​

Answer 1

volume of cone eight times

Answer 2

We know,

$\boxed{\sf{Volume \ of \ a \ cone = \dfrac{1}{3}\pi r^2 h}}$

If the height of the cone is tripled and the radius is doubled then:

$\sf{\implies Volume = \dfrac{1}{3}\pi (2r^2)(3h)}$

But here the volume of the cone is  $\sf{\dfrac{1}{3}\pi r^2 }$.

$\sf{\implies Volume=2\times 3( \dfrac{1}{3}\pi r^2 )}$

$\sf{\implies Volume=6( \dfrac{1}{3}\pi r^2 )}$

$\boxed{\sf{\therefore Volume=6( \dfrac{1}{3}\pi r^2 )}}$

∴ The volume will become 6 times​.