Question

If the height of the orbit of a satellite increase, its velocity must also increase ?​

Answer 1

Explanation:

false. because velocity is indirectly proportional to square root of R+H

where R is radius of the earth and H is the distance of the orbit from the surface of the earth.

Answer 2

Answer:

FA|SE

Explanation:

The eccentricity of the orbit would increase. Assuming the orbit began as perfectly circular, the point in the orbit where the acceleration took place would become the perigee (nearest approach). The opposite point in the orbit would become the apogee (most distant point from Earth). As far as determining the new eccentricity,more information is needed. The formula would be:

e=[1+(2Eh^2)/(GM)^2]^(1/2)

E= orbital energy

h= Specific relative angular momentum

G= gravitational constant (6.7×10−11 m3⋅kg−1⋅s−2 or so)

M= mass

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