Question

if the hieght of the object is 1.2 in conex miror with rAdhius of curvature 12 cm find the position of IMAGE. ANSWER[0.4]​​

Answer 1

Answer:

Answer:

ANSWER

Since radius of curvature is 1.2m i.e. 120cm.

Therefore focal length=−60cm

From mirror formula

v

1

+

u

1

=

f

1

−35

1

+

u

1

=

−60

1

u

1

=

35

1

−

60

1

u

1

=

420

12−7

u=84cm

Image height=

84

12

×35=5cm

Thus image height will be 5 cm.

Explanation:

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Answer 2

Answer:

length = 60 cm

$\frac{1}{ - 35} + \frac{1}{x} = \frac{1}{ - 60} \\ \ \frac{1}{x} = \frac{1x12}{35x12} - \frac{1x7}{60x7} \\ \frac{12 - 7}{420}$

$\frac{5 \div }{420 \div 5} = 84cm$

height -

$\frac{12}{84} \times 35 = 5$

5cm is the answer