Question

if the hight of the cylinder becomes 1/4 of the orginal hight and the radius is doubled ,then the curved surface area of the new cylinder is equal to how many times the orginal cylinder
please say the correct answer . don't spame

Answer 1

Step-by-step explanation:

Curved Surface area (CSA) of Original Cylinder

= 2 π r h

( CSA By formula )

CSA of New Cylinder = 2 π × 2r × 1/4h

= 4 π r × 1 / 4h

= π r h

CSA of Original Cylinder was / is twice the CSA of New Cylinder.