Question

If the horizontal distance between the mean position and extreme position of oscillating spring is
30cm, then what is the value of the amplitude in SI units.​

Answer 1

0.3m
As we consider a pandulum which is displaced from the mean position as it makes and angel of 90 with its mean position so the vertical length og pandulum os equal to the horizontal distance is equal to its amplitude so it will be 30 cm 1oo cm is equal to 1 m so divide by 100 you will get 0.3m which is si unit